Two touching bars 1 and 2 are placed on an inclined plane forming an angle α with the horizontal shown in Figure.

Hi, I have a question and I hope anyone could answer it:

Two touching bars 1 and 2 are placed on an inclined plane forming an angle α with the horizontal shown in Figure. The masses of the bars are equal to m1 and m2 and the coefficients of friction between the inclined plane and the bars are equal to k1 and k2 respectively, with k1 > k2 . Find

(a) The force of interaction of the bars in the process of motion;

(b) The minimum value of the angle α at which the bars start sliding down.

• 0
Share

Let us indicate the positive direction of the x-axis along the incline (Fig.). Figures show the force diagram for the blocks.

Let, R be the force of interaction between the bars and they are sliding down with the same constant acceleration w.  Newton’s second law of motion in projection form along the x-axis for the blocks gives: (b) when the block just slides down the plane w=0, so from Eqn. (3) 