Hi, I have a question and I hope anyone could answer it:
Potassium chlorate is prepared by electrolysis of KCl in basic solution as shown by following equation.
6OH– + Cl– → ClO3 – + 3H2O + 6e–
A current of xA has to be passed for 10h to produce 10.0g of potassium chlorate. the value of x is ….. (Nearest integer)
(Molar mass of KClO3 = 122.6 g mol-1 F = 96500 C)