An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram.

Hi, I have a question and I hope anyone could answer it:

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram.

If Q1, Q2, Q3 indicate the heat absorbed by the gas along the three processes and ΔU1 ,ΔU2, ΔU3 indicate the change in internal energy along the three processes respectively, then

(a) Q1 > Q2 > Qand ΔU1 = ΔU2 = ΔU3

(b) Q3 > Q2 > Q1 and  ΔU1 = ΔU2 = ΔU3

(c) Q1 = Q2 = Q3 and ΔU1 > ΔU2 > ΔU3

(d) Q3 > Q2 > Q1 and ΔU1 > ΔU2 >ΔU3

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1 Answer

  1. Correct option is D)
    dU1=dU2=dU3
    Q1>Q2>Q3
    Because
    ΔQ=ΔW+dU
    Change in internal energy independent of path and work depends on path and the heat required increases as the work done increases.
     ΔQ1>ΔQ2>ΔQ3