A cyclist is riding with a speed of 27 kmh^-1. As he approaches a circular turn on the road of radius 80.0 m,

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A cyclist is riding with a speed of 27 kmh-1. As he approaches a circular turn on the road of radius 80.0 m, he applies brakes and reduces his speed at a constant rate of 0.5 ms-1 per second. Find the magnitude of the net acceleration of the cyclist.

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  1. Answer:

    Let us suppose, the cyclist applies brakes at the point A of the circular turn.Then retardation produced due to brakes (a1) will act opposite to the velocity (v) Thus, aT = -0.5 ms-2 Total acceleration is given by:

    Let us suppose, the cyclist applies brakes at point A of the circular turn. Then retardation produced due to brakes (a1) will act opposite to the velocity (v) Thus, aT = -0.5 ms-2 Total acceleration is given by